Date: 2009-07-26 11:04 am (UTC)
The probability that he will suffer an injury in one event is x = 0.12
The probability that he will NOT suffer an injury in one event is (1 - x) = (1.0 - 0.12) = .88
The probability that he will NOT suffer an injury in any of n events is .88^n or (1 - x)^n
So, the probability that he will be injured in n events is 1 - ((1 - x)^n)
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Elf Sternberg

May 2025

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